Algebra (reciprocal)?

1 ⤊

Algebra (reciprocal)?

how do you find the reciprocal of 3-2i?

2007-10-23 02:41:39 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

3 answers

1/3-2i then multiply numerator and denominator by the conjugate 3 + 2i

1(3 + 2i)/(3-2i)(3+2i)
=(3+2i)/(9 - 4i^2)
= (3+2i) /(9 + 4)
= (3+2i)/13
=3/13 + 2i/13

2007-10-23 02:51:09 · answer #1 · answered by Linda K 5 · 1⤊ 0⤋

Just multiply the top and bottom by the conjugate and divide by the real number you get in the denominator.

1/(3-2i) = (3+2i)/((3+2i)*(3-2i) = (3+2i)/(9+4) = (3/13) + (2/13)i.

Doug

2007-10-23 02:53:27 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋

1/(3-2i)

2007-10-23 02:48:24 · answer #3 · answered by orangejuice 2 · 0⤊ 0⤋