can someone simplify this expression for me ,, with steps please!!
cos^2 (2x) - sin^2 (2x)
2007-10-23 02:07:54 · 5 answers · asked by Labuuu* 1 in Science & Mathematics ➔ Mathematics
cos ² θ - sin ² θ = cos 2 θ
cos ² 2x - sin ² 2x = cos 4x
2007-10-23 04:32:05 · answer #1 · answered by Como 7 · 0⤊ 0⤋
cos^2 (2x) - sin^2 (2x)
= cos 4x
remember the trigonometri formula
cos 2x = cos^2 x - sin^2 x
and
cos x = cos^2 (x/2) - sin^2 (x/2)
2007-10-23 09:33:43 · answer #2 · answered by imieazmi 2 · 0⤊ 0⤋
cos^2 (x) - sin^2 (x)= cos 2x
so therefore
cos^2 (2x) - sin^2 (2x) = cos2*(2x)
which is cos 4x
2007-10-23 09:12:30 · answer #3 · answered by Siva 5 · 1⤊ 0⤋
cos^2 (2x) - sin^2 (2x) = cos 2(2x) = cos 4x
2007-10-23 09:24:41 · answer #4 · answered by Adrianne G. 2 · 0⤊ 0⤋
I belive it might be as simple as cos2(2x) but what is it you are trying to simplify it to
becasuse cos^2(theta)-sin^2(theta)= cos2(theta)
http://en.wikipedia.org/wiki/List_of_trigonometric_identities#Product-to-sum_and_sum-to-product_identities
2007-10-23 09:21:32 · answer #5 · answered by Anonymous · 0⤊ 0⤋