Can someone help me with these questions?Please.?

Question

1. The area of a gymnasium floor is 264 square yards. The floor is 11 yards wide. How long is the floor?
A.253 yards
B.24 yards
C.11 yards
D.242 yards

2.The area of a square piece of cardboard is 81 sq.in. What is the length of the cardboard?
A.6.28in
B.3.14in
C.8in
D.9in

3.How much water can be held by a cylindrical tank with a radius of 12 feet and a height of 30 feet?
A.13,564.8 cubic feet
B.2,260.8 cubic feet
C.33,912 cubic feet
D.54,259.20 cubic feet

Answer 1

1. 264/11 = 24, B

2. x^2 = 81, so x=9, D

3. V = 12^2(pi)30 = 144(pi)30 = 4320pi ~ 13500 or so, A

Answer 2

1) To get the length, just divide the area by the length.
264 ÷ 11 = 24 yards = (B)

2) The cardboard is a square, meaning that the length and width are the same size. To get the length, just take the square root of the area.
√(81) = 9 in. = (D)

3) You need to get the volume of the cylinder. That is given by the formula: V = π(r^2)h. Solve for r = 12, and h = 30
π(12^2)(30)
π(144)(30)
~ 13,564.8 cubic feet = (A)

Answer 3

for the first question, divide 264 by 11 for your answer... the answer is 24..

for the second question, because the piece of cardboard is a SQUARE, the length would equal the width... 9 times 9 equals 81, so the length AND width are both 9 inches.

for the third question.. I don't know this one. I feel stupid.

Answer 4

the aswer of # 1 Q is B because 264/11=24

the answer of # 2 Q is D because 81=9*9

the answer of # 3 Q is A because V=12*12*30*3.14

Answer 5

1. A = 264 = 11x

x = 24sq.yds, Answer C

2. square of 81 = 9in, Answer : D

3. V = 3.1416 x 12^2 x 30 = 13,571.71cu.ft closest answer is A

Answer 6

1)
264/11=24
B.24 yards

2)
sqrt(81)=9
D.9in

3)
V=3.14 * 12*12*30
=13564.8
A.13,564.8 cubic feet

Answer 7

axis of symetry is the equation of a line that bisects the object in symetrical products. so for a parabola if the vertex is on the y axis that's x=0 if the vertex have been at x=5/13 then the axis of symetry would be x=5/13. vertex is got here across using x=-b/2a then plug it in to the equation to resolve for y. the place ax^2+bx+c