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always perpendicular, no matter what the shape of the curve is.

2007-10-22 18:21:34 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

Any component of acceleration in the direction of the particle will change its speed. Therefore, the acceleration must always be perpendicular to the instantaneous direction of travel, although it can vary in magnitude, which will vary the shape of the curve.

2007-10-22 18:53:12 · answer #1 · answered by Helmut 7 · 0 0

v= a(t) *i+b(t) j+c(t)*k with a^2+b^2+c^2 =constant
@= da/dt*i+db/dt*j+dc/dt k
and a*da/dt +b*db/dt+c*dc/dt =0 (x)
Take the dot product of v and @ which is precisely the expression (x)
so it is 0 and the vectors are perpendicular

2007-10-23 08:26:24 · answer #2 · answered by santmann2002 7 · 0 0

Show that it velocity and acceleration are?............

...............................

Please take your time to rethink your question. Ask that question to yourself and think if you could find a answer to this rethorik masterpiece.

2007-10-23 01:25:37 · answer #3 · answered by Marcus Paul 3 · 0 0

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