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how do you do this??? please show me how you got your answer

write an algebraic expression for the given expression.
- sin(arccos x)

- sec(arctan 3x)

2007-10-22 17:45:53 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

Using the unit circle, if
cosθ = x
the side adjacent to θ is x,
the hypotenuse is 1, so
the side opposite to θ must be √(1 - x^2), so
sin(arccos x) = √(1 - x^2)

Using slightly different reasoning for
sec(arctan 3x),
if tanθ = 3x
let the side opposite to θ = 3x,
the side adjacent to θ is 1, and
the hypotenuse is √((3x)^2 + 1), so
sec(arctan 3x) = √((3x)^2 + 1)

2007-10-22 18:12:04 · answer #1 · answered by Helmut 7 · 0 0

arc (function) is the inverse of the function:

arccos = cos^-1

sin (cos^-1 x)

sec ( tan^-1 3x)

2007-10-22 17:51:00 · answer #2 · answered by sayamiam 6 · 0 0

the crap they teach in school now days!! you do not use this stuff in real life!!!

2007-10-22 17:58:40 · answer #3 · answered by david s 4 · 0 1

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