ok, im kinda stuck on this one. heres the question
11. Factor 32x^3 – 32x^2 + 8x by finding the GCF. Be sure to factor completely. If this is not possible for some reason, state why.
heres what i got, but i cant figure out how to factor out the last quadratic left in the parenthesis. can some one help me please
8(4x^3-4x^2+1)
2007-10-22 17:40:54 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
32x^3 - 32x^2 + 8x
= 8x (4x^2 - 4x +1)
= 8x (2x-1)^2
just try to remember the formula,
A^2 + 2AB + B^2 = (A+B)^2
2007-10-22 17:57:03 · answer #1 · answered by hugo 2 · 0⤊ 0⤋
Hi , I am from Brazil and can help you .
First put the question :
32 x ³ - 32 x² + 8x =0
The next step is find a value that be common
In this case is 8x . Why ?
Because 32 can be dividied by 8 and x can be dividied by x²
8x * ( 4 x ² - 4 x + 1 ) = 0
8x = 0
x = 0/8 = 0
4 x² - 4x +1 = 0
x = 1/2
Substitute this value ( 1/2 ) in 4 x² - 4x + 1 = 0 and find the value o , the same result you find when substitute ( 1/2 ) in
32 x³ - 32 x² + 8x = 0
Observation : My nickname in your country is told white , here in Brazil is Branco .
Bye , sucess , health and peace
2007-10-23 01:03:38 · answer #2 · answered by Branco 5 · 0⤊ 0⤋
32x^3 – 32x^2 + 8x = 8x( 4x^2 -4x +1)
8x( 2x-1)^2
2007-10-23 00:48:24 · answer #3 · answered by sayamiam 6 · 0⤊ 0⤋
the greatest common factor is 8x, so if you take that out...
8x(4x^2-4x+1)
and the stuff in the parenthesis factors out to
8x(2x-1)^2
There ya go!!
2007-10-23 00:50:42 · answer #4 · answered by mathnerd 3 · 0⤊ 0⤋
32x³ - 32x² + 8x = 8x(4x² - 4x + 1) = 8x(2x - 1)²
2007-10-23 00:48:21 · answer #5 · answered by Northstar 7 · 1⤊ 0⤋