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derivative:

f(x)=7x^6 - 8/x^3 + 3(sq root of x)


antiderivative:

x^7 + 4/x^2 + 3/2x + C

2007-10-22 17:07:32 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

I = ∫ 7x^6 dx - 8 ∫ x^(-3) dx + 3 ∫ x^(1/2) dx
I = x^7 + 4 x^(- 2) + 3 x^(3/2) / (3/2) + C
I = x^7 + 4 / x ² + 2 x^(3/2) + C

2007-10-22 20:22:24 · answer #1 · answered by Como 7 · 0 0

Just the term corresponding to the square root is incorrect.

sqrt(x) = x^(1/2), and when you find an antiderivative of power (not -1), you add one to the power, then divide by the new power.

x^n -> x^(n+1)/(n+1), unless n = -1.

2007-10-22 17:18:17 · answer #2 · answered by ♣ K-Dub ♣ 6 · 0 0

no. the 1st term is ok.( i.e. x raised to 7). the 3rd term is incorrect. (3/2x.) it should be 2 x raised to 3/2.

2007-10-22 17:25:56 · answer #3 · answered by amit p 2 · 0 0

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