KOH + BaCl2 -------------> BaOH2 + KCl
2007-10-22 15:45:29 · 5 answers · asked by HAPPY <3 2 in Science & Mathematics ➔ Chemistry
Your problem is that you written barium hydroxide incorrectly.
It is Ba(OH)2. The entire hydroxide anioin has to be doubled, not just the hydrogen atom.
Now the balancing is easy
2KOH + BaCl2 == Ba(OH)2 + 2 KCl
2007-10-22 15:50:23 · answer #1 · answered by reb1240 7 · 1⤊ 0⤋
Write the formulas of the individual reactants and products correctly first.
2KOH + BaCl2 ---> Ba(OH)2 + 2KCl
2007-10-22 15:50:08 · answer #2 · answered by papastolte 6 · 1⤊ 0⤋
"BaOH2" should be "Ba(OH)2 "
Balanced eq.
2KOH + BaCl2 = Ba(OH)2 + 2KCl
2007-10-22 15:49:08 · answer #3 · answered by Dr. K 3 · 1⤊ 0⤋
2KOH + BaCl2 ---> BaOH2 + 2KCl
2007-10-22 15:51:18 · answer #4 · answered by DynamiteAnswers 2 · 1⤊ 0⤋
be independent think really hard
2016-05-24 22:33:02 · answer #5 · answered by ? 3 · 0⤊ 0⤋