2007-10-22 15:07:34 · 2 answers · asked by Rose R 1 in Science & Mathematics ➔ Chemistry
Normally, when you have an equlibrium reaction, an increase in presure will drive the reaction in the direction where there are the least moles of gaseous material. Your reaction appears to involve formation of a sugar, or perhaps starch or cellulose (which are all solids), from CO2 and H2O (vapor) it would drive it to the right. Because this process normally goes on in plant cells and there are multiple steps, enzymes, catalysts etc involved, it might behave differently than something in a reaction vessel. It would be interesting to subject a tree to higher pressures and see if more oxygen would be created!
2007-10-22 15:23:23 · answer #1 · answered by Flying Dragon 7 · 0⤊ 0⤋
Is H2O gas or liquid? It would make a big difference in this question.
If H2O is liquid, then nothing would happen (same volume of gas on each side)
If H2O is gaseous, decreasing the volume increases the pressure, and the reaction would be forced to the right (products) to reduce the volume of the two gases, and their pressure.
2007-10-22 15:17:55 · answer #2 · answered by papastolte 6 · 0⤊ 0⤋