2007-10-22 13:45:14 · 12 answers · asked by Anonymous in Entertainment & Music ➔ Polls & Surveys
http://answers.yahoo.com/question/index;_ylt=AmSehyPmZmQg6YQ9BwycBpXsy6IX;_ylv=3?qid=20071022172948AAVIlWF
2007-10-22 13:45:24 · update #1
Well, believe it or not...sometimes I do get pretty sick of myself too!
2007-10-22 14:00:56 · answer #1 · answered by Anonymous · 3⤊ 0⤋
Well honey, to be frank though. Our characters are somewhat similar to the magnetic polarity in a way that North and South attracts whilst the similar poles in North and North or South and South repels.
If that happens, there's no way that I can be my own best friend as we are similar in characters, know each other too well that when one is good, the other will strive to be even better. That's one reason human beings are struggling most of the time as they have yet to find their true self though.
Cheers and have a nice week ahead :)
2007-10-23 13:06:18 · answer #2 · answered by Larry L - Hi Everyone :D 6 · 0⤊ 0⤋
No
I would probably dump me for a blonde and a brunnette and having my buttons punched all the time.
2007-10-22 15:08:48 · answer #3 · answered by LORD Z 7 · 2⤊ 0⤋
I'm not my own BF, but I am an introvert, so enjoying my own company comes naturally to me.
2007-10-22 14:16:48 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Yes definitely and I have a few bestfriend then...my shadow, my soul and also my spirit. They are so close to me.
2007-10-22 21:53:39 · answer #5 · answered by † Iríšh † 7 · 1⤊ 0⤋
I couldn't be my own best friend unless I did.
2007-10-22 17:06:41 · answer #6 · answered by ? 5 · 0⤊ 0⤋
I do not know, I never think about that. Take care.
2007-10-22 14:05:45 · answer #7 · answered by Jack Jack 4 · 0⤊ 0⤋
I don't know. I can be kind of outrageous, loud & obnoxious. And those kind of people annoy me :P
2007-10-22 13:59:23 · answer #8 · answered by LADY beautiful mind (is sexy) 5 · 0⤊ 0⤋
ummm maybe
2007-10-22 23:18:53 · answer #9 · answered by anna 7 · 0⤊ 0⤋
if i was, then yeah, but im not
2007-10-22 13:50:30 · answer #10 · answered by Kenny 5 · 2⤊ 0⤋