Solve. (x + 4)^2 = 4?

Question

Solve. (x + 4)^2 = 4

Answer 1

x + 4 = ± 2
x = - 4 ± 2
x = - 2 , x = - 6

Answer 2

Many people gave you the right answers (-2, -6), but nobody gave you the correct way to solve the problem. First, set up the equation in the form aX^2 + bX + c = 0. Then . . .

USE THE QUADRATIC EQUATION

X = {-b +/- Sqrt(b^2 -4ac)}/2a

Their simple method of taking the square root of both sides only works for simple equations, like this one happens to be. The quadratic equation works for ALL equations of this form, and even finds imaginary solutions.

Answer 3

(x + 4)^2 = 4
x + 4 = +- 2
x = - 2, x = - 6

Or you could expand the left

x^2 + 8x + 16 = 4
x^2 + 8x + 12 = 0
(x + 2)(x + 6) = 0
x = - 2, x = - 6

Answer 4

(x + 4)^2 = 4?

x+4 = +2 or (x+4) =-2

Solutions

x1 = 2-4 =-2

x2 = -2-4 =-6

Answer 5

Square root each side

x + 4 = 2

then solve for x

x = 2 - 4

x = -2

also the square root of 4 can be -2

x + 4 = -2

x = -6

So....... x can = -2 or -6

Answer 6

yes square root both sides - trust me i'm a math teacher you get a positive and a negative result and both answers must be considered
x+4 = +2 x=2-4 = -2
or x+4 =-2 x=-2-4 = -6

Answer 7

x^2 + 8x + 16 = 4
x^2 + 8x + 12 = 0
x^2 + 6x + 2x + 12 = 0
x (x+6) + 2(x +6) = 0
(x+2) (x+6) = 0
x = -2 or x = -6

Answer 8

don't take the square root; you'll only get one answer.

x^2 + 8x + 16 - 4 = 0

x^2 + 8x + 12 = 0

(x+2)(x+6) = 0

x = -2, -6

Answer 9

take the square root of each side
x + 4 = 2
x = -2