2007-10-22 13:22:11 · 7 answers · asked by mikegemmati 1 in Science & Mathematics ➔ Mathematics
(2x² + 5)(2x² + 5)
4 x^4 + 20 x ² + 25
2007-10-24 07:04:32 · answer #1 · answered by Como 7 · 1⤊ 0⤋
(2x^2 + 5)^2 is the same as multiplying
(2x^2 + 5)(2x^2 + 5)
Use FOIL
Distribute(multiply)the 2x^2 to the 2x^2
Distribute the 2x^2 onto the 5
Distribute the 5 onto the 2x^2
Distribute the 5 onto the 5
You should get:
4x^4 + 10x^2 + 10x^2+ 25
Your final answer is 4x^4 +20x^2+25
2007-10-22 20:31:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(2x^2+5)(2x^2+5)
4x^4 +10x^2+10x^2 + 25
4x^4 +20x^2 +25
2007-10-22 20:24:26 · answer #3 · answered by Ms. Exxclusive 5 · 0⤊ 0⤋
(2x^2 + 5)^2
= (2x^2)^2 + 2(5)(2x^2) + (5)^2
= 4x^4 + 20x^2 + 25
2007-10-22 20:28:21 · answer #4 · answered by ideaquest 7 · 0⤊ 0⤋
(2x^2+5)(2x^2+5)
4x^4+10x^2+10x^2+25
4x^4+20x^2+25
Step 1: Do FOIL
(Front Outer Inner Last)
Front: 2x^2 times 2x^2 which gives you 4x^4
Outer: 2x^2 times 5 gives you 10x^2
Inner: 2x^2 times 5 gives you 10x^2
Last: 5 times 5 gives you 25
Then you add all these up and it will give you 4x^4+20x^2+25.
2007-10-22 20:40:17 · answer #5 · answered by Oli-NYC 6 · 0⤊ 0⤋
(a+b)^2=a^2+2ab+b^2
a=2x^2
b=5
(2x^2)^2 + 2 (2x^2)(5) + 5^2
=4x^4+20x^2+25
2007-10-22 20:30:05 · answer #6 · answered by cidyah 7 · 0⤊ 0⤋
[11]
it is 4x^4+20x^2+25
(2x^2 +5)^2
=(2x^2)^2+2*2x^2*5+5^2
=4x^4+20x^2+25
2007-10-22 20:25:06 · answer #7 · answered by alpha 7 · 0⤊ 0⤋