Using this info:
E is between D and F.
DE = 4x + 2,
EF = 3x, and
DF = 16
DE = ???
A. - 70
B. - 6
C. 10
D. 58
2007-10-22 12:05:17 · 5 answers · asked by *:)* 1 in Science & Mathematics ➔ Mathematics
Remember DE+EF=DF.
Substitute the equation:
DE+EF=DF
4X + 2 + 3X = 16
7X + 2 = 16
7X + 2 - 2 = 16 - 2
7X = 14
X = 2
Substitute X in DE:
DE = 4X + 2
DE = 4(2) + 2
DE = 8 + 2
DE = 10
Answer: c.10
2007-10-22 12:16:59 · answer #1 · answered by Anonymous · 0⤊ 0⤋
C.10
2007-10-22 19:11:00 · answer #2 · answered by ♥♥felisha♥♥ 5 · 0⤊ 0⤋
C. 10
2007-10-22 19:08:24 · answer #3 · answered by Steve T 5 · 0⤊ 0⤋
Since E is between D and F, the long segment DF is split into two segments DE and EF. You know that the long segment (DF) is 16, so you should already have an idea of what DE will be. It certainly won't be negative or bigger than DF. :-)
Anyway following through algebraically, we know:
DE + EF = DF
(4x + 2) + 3x = 16
7x + 2 = 16
7x = 14
x = 2
DE = 4x + 2
DE = 4(2) + 2
DE = 10
Answer C: 10
2007-10-22 19:09:11 · answer #4 · answered by Puzzling 7 · 0⤊ 0⤋
c
2007-10-22 19:12:57 · answer #5 · answered by Anonymous · 0⤊ 0⤋