Let f(x)=1/(1+x^2) and find the absolute minimum and absolute maximum values of f on the closed interval [2, 4

Answer 1

f´(x) =-2x/(1+x^2)^2 <0 in the given interval so the function is decreasing and the max is at x=2 y=1/5 and the minimum at x=4
y= 1/17