If a bacterial protein has 30 amino acids, how many nucleotides are needed to encode it?

Question

-90
-600
-93
-30
-33

Answer 1

It depends how technical you want to be.

Each amino acid requires three nucleotides to code it. So it would seem that 90 would be the correct answer.

More correctly, you will need a start and a stop signal as well. You might be able to do without the start (by keeping the methionine that comes from the start codon), but not the stop. Each of those is another 3 nucleotides, of course, so a more correct answer would be 93.

If you want to get really bizarre, some proteins are made of repeating subunits or have large sections removed before they are encoded into amino acids or after they are made into proteins. So a PARTICULAR protein might have much less or much, much more. Given that none of these particulars are mentioned, it's probably safe to assume they're not happening.

Likewise, the DNA itself will have lots of other regions that aren't transcribed but are necessary for the protein to be transcribed. Again, probably beyond the purveiw of the question.

Answer 2

decision D 30 amino acids = ninety nucleotides even nonetheless that is barely a minimal of ninety nucleotides required, the gene itself could be larger than that thinking the regulatory sequences.

Answer 3

each amino acid needs 3 nucleotide so it should be 90 but the final amino acid dosent have codon so 87 are needed