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4 answers

Intuitively you can reason as follows:
If only kids come, they will sell $100 worth of tickets. However, for each adult that comes, they make an additional $1 in ticket sales. Since the total sales were $135, there must have been 35 adults (and 15 kids).

You can also solve this algebraically:
Let A be the number of adults tickets sold.
Let 50-A be the number of kids tickets sold

3A + 2(50 -A) = 135
3A + 100 - 2A = 135
A = 35

50-A = 15.

So 35 adult tickets, 15 kids tickets.

Double-check:
35 * $3 + 15 * $2= $105 + $30 = $135

2007-10-22 11:27:13 · answer #1 · answered by Puzzling 7 · 0 0

k + a = 50
2k + 3a = 135

k = -a +50

2(-a +50) + 3a = 135
-2a + 100 + 3a = 135
a = 35

k = -35 + 50
k = 15

Check:
15 + 35 = 50 2(15) + 3(35) = 135
50 = 50 30 + 105 = 135
135 = 135

So they sold 15 kid tickets and 35 adult tickets

2007-10-22 11:26:09 · answer #2 · answered by Ms. Exxclusive 5 · 0 0

Kids = 15 and Adults = 35

2007-10-22 11:28:04 · answer #3 · answered by Steve T 5 · 0 0

15 kids
35 adults

2007-10-22 11:27:23 · answer #4 · answered by mahima 2 · 0 0

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