Help with a geometric sequence? Points to Best Answer!?

Question

Find the 5th term for the geometric sequence with the first term=6 and the third term is 2/3\
Tell me how you did it, please?

Answer 1

2nd term 6*r
3rt term 6*r^2 so fifth term =6*r^4
6r^2=2/3 so r^2=1/9 and r=+-1/3 both can be so
5th term = 6*/81 =2/27

Answer 2

From inspection, you can see to get from 6(1st term) to (2/3)(3rd term), you have to divide by 3, continuously, or if you like multiply by 1/3, continuously.
1st: 6, 2nd: 6*(1/3)=2, 3rd: (2*(1/3))=2/3, 4th: (2/3)*(1/3)=(2/9), 5th: (2/9)*(1/3)=2/27

So, as you can see the answer 2/27.