2007-10-22 09:59:09 · 7 answers · asked by tcooper19 1 in Science & Mathematics ➔ Mathematics
y = ∫ 6x³ / (x^4 - 7) dx
Let u = x^4 - 7
du = 4x³ dx
(3/2)du = 6x³ dx
y = (3/2) ∫ du / u^(1/2)
y = (3/2) ∫ u^(-1/2) du
y = 3 u^(1/2) + C
y = 3 (x^4 - 7)^(1/2) + C
2007-10-22 10:40:55 · answer #1 · answered by Como 7 · 0⤊ 0⤋
i think your best strategy would be to multiply both sides of the equation by dx, and then integrate. when you integrate dy, you will just get y. when you integrate the other side (6x^3/sqrt(x^4-7) dx), make a u-substitution with u=x^4-7, du=4x^3dx. you will have a pretty easy integral to solve, and when you substitute x^4-7 back in for u, you will have y=your answer.
2007-10-22 10:04:50 · answer #2 · answered by Kaila G 3 · 1⤊ 0⤋
this would't be solved analytically, by way of fact the differential equation is nonlinear, and not separable. attempt Euler's technique, with various step length, in case you like a definite y value (eg y(a million)). Dang, i did not see that the equation become separable. supply the BA to the guy under, for specific. stable practice guy!
2016-11-09 05:22:10 · answer #3 · answered by Anonymous · 0⤊ 0⤋
You solve it. Do your homework!!
2007-10-22 10:01:37 · answer #4 · answered by Fon 2 · 0⤊ 2⤋
dont have the time sorry
2007-10-22 10:04:02 · answer #5 · answered by I♥Hockey 2 · 0⤊ 2⤋
i dont know
2007-10-22 10:02:33 · answer #6 · answered by Anonymous · 0⤊ 2⤋
STOP ASKING THAT!!!
2007-10-22 10:02:57 · answer #7 · answered by lizll101 2 · 0⤊ 1⤋