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2 answers

∫2x(5 -√x)dx
∫10x - 2x^3/2
let u = x
du=dx
so
∫10u - 2u^3/2
(10u^2)/2 - 2/5(2)u^5/2 du
5x^2 - (4/5x^5/2) + C

2007-10-22 10:00:33 · answer #1 · answered by Anonymous · 2 0

Let u = sqrt(x), u^2 = x, 2u du = dx. The integrand becomes a polynomial in u.

2007-10-22 09:50:26 · answer #2 · answered by Tony 7 · 0 0

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