help with equations please?

Question

1) y+a over 3= c ...solve for y

2) k= prt... solve for r

3) H= ( 0.24 ) j^2 Rt............solve for R

Please and thank you so much!

Answer 1

Question 1
(y + a)/3 = c
y + a = 3c
y = 3c - a

Question 2
r = k/(pt)

Question 3
R = H / (0.24 j² t)

Answer 2

1) (y+a)/ 3= c ...solve for y
y+a = 3c
y = 3c-a

2) k= prt... solve for r
k/pt = r

3) H= ( 0.24 ) j^2 Rt............solve for R
H/(.24j^2t = R

Answer 3

y= 3c-a
r = k/pt
R= H/(0.24)(j^2)(t)