what is the angular momentum of the moon about the planet?

Question

There is a moon orbiting an Earth like planet. The mass of the moon is 4.74 x 10^22 kg, the center to center separation of the planet and the moon is 285,000 km, the orbital period of the moon is 27.7 days, and the radius of the moon is 1770 km. What is the angular momentum of the moon about the planet? Answer in units of kg m^2/s.

Answer 1

Angular momentum can be defined as
L=R x p (vector product)

R - radius of rotation
p - linear momentum

p=mV

L=RmV

Or also L=Iw
I-moment of inertia for point mass I=mR^2
w - angular speed
( just for for fun L=mR^2 (V/R)= RmV ( I guess it was just as good ...)

w= 2 pi / (27.7 x 24x3600) - rad /sec

So L=mR^2 w
L= 4.74 E+22 (285E+6)^2 2 pi / (27.7 x 24x3600)=
L=35.5 E+24 kg m^2/s.