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A grinding wheel is in the form of a uniform solid disk of radius 6.33 cm and mass 1.3 kg. It starts from rest and accelerates uniformly under the action of the constant torque of 0.793 Nm that the motor exerts on the wheel.
-How long does the wheel take to reach its final speed of 1590 rev/min? Answer in s.
b) Through how many revolutions does it turn while accelerating? Answer in rev.
Please help!!!! THANKSS!!!

2007-10-22 09:26:24 · 1 answers · asked by Ron108 1 in Science & Mathematics Physics

1 answers

Angular speed
omega=At + initial omega ( initial omega=0)

Torque or angula force can be expressed as
T=I A
I -moment of inertia
A angular acceleration

I=(1/2) mR^2
finally we have

omega=(T/I)t
omega=(2T/ (mR^2))t

b) Angle = (1/2) A t^2
revolutions =Angle/2 pi

2007-10-23 09:11:04 · answer #1 · answered by Edward 7 · 0 0

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