Find two quadratic unctions with zeros x= -1 and x=2.........I already found one of the equations which ended up being x^2-x+2 but im not sure on how to find the second equation
Thanks you math people...I'd be lost with out yous
2007-10-22 06:50:54 · 3 answers · asked by ELECTRA 1 in Science & Mathematics ➔ Mathematics
Um, any function that zeroes at -1 you can factor (x+1) out of, and any that zeroes at 2 will have an (x-2). The only quadratic that zeroes at both is (x+1)(x-2)= x^2-x-2. There can't be any other second degree equations with both roots unless you're just multiplying coefficients (2x^2-2x-4).
2007-10-22 06:56:45 · answer #1 · answered by JP 3 · 0⤊ 0⤋
f(x) x^2 - x - 2 = 0
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A second equation? Maybe f(x) = 3x^2 - 3x - 6
The form is:
ax^2 - a(x1 + x2)x + ax1 * x2 = 0
where x1, x2 are the zeros
2007-10-22 14:00:01 · answer #2 · answered by Amit Y 5 · 0⤊ 0⤋
(x+1)(x-2)=0, or x^2-x-2 = 0.
Also 17x^2 -17x-34=0
2007-10-22 13:55:42 · answer #3 · answered by fcas80 7 · 0⤊ 0⤋