English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

z answer is -0.197+0.09i

2007-10-22 04:57:40 · 2 answers · asked by yuft 2 in Science & Mathematics Mathematics

2 answers

I'm guessing that z is complex, so write it as a+jb, plug that in for z, do the arithmetic, and you'll get something that looks like
a+jb = n+mj where n and m are numerical values and that's your complex value for z.

Doug

2007-10-22 05:08:03 · answer #1 · answered by doug_donaghue 7 · 0 1

Let z = a+ib and [z+2-i]/[z+1] = M+Ni

M+Ni = [(a+2)+(b-1)i] / [(a+1)+ib]

Multiply conjugate, [(a+1)-ib]/[(a+1)-ib] and comparing real and imaginary element respectively.

Real coefficient: M
M = [(a+2)(a+1) + b(b-1)] / [(a+1)^2+b^2]

Imaginary coefficient: N
N = [(b-1)(a+1) - b(a+2)] / [(a+1)^2+b^2]

Finally
z.[z+2-i]/[z+1]
= (a+ib)(M+Ni)
= (aM-bN) + i(bM+aN)

2007-10-24 01:47:49 · answer #2 · answered by cllau74 4 · 0 0

fedest.com, questions and answers