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f `(x) = (1/3)(x + 2)^(-2/3) - 1
f "(x) = (- 4/9) (x + 2)^( - 5/3 )
f "(x) = (- 4) / [ 9 (x + 2)^( 5/3 ) ]

2007-10-22 07:19:06 · answer #1 · answered by Como 7 · 0 0

How about...

d/dx (x+2)^1/3 - (x+2) = 1/3(x+2)^-2/3 - 1
d2/dx2 (x+2)^1/3 - (x+2) = -1/3(x+2)^-5/3

Been many many years. Prob completely wrong :)

2007-10-22 11:11:57 · answer #2 · answered by Barry G 1 · 0 0

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