The Length of the latus rectum is the square root of two and the eccentricty is 4. Any suggestions on how to solve it?
2007-10-22 03:12:20 · 4 answers · asked by Scarlet Mist 2 in Science & Mathematics ➔ Mathematics
there is still a missing description
the hyperbola can be oriented up/down or left/right... this cannot be covered by the length of latus rectum or the eccentricity...
plus... there are no fixed point... where is the center/ any vertex/ any focus...
eccentricity = e = c/a = 4.
length of latus rectum = LLR
now, e^2 - 1 = LLR^2 / b^2
and since c^2 = a^2 + b^2 ...
you can only get a, b and c... but no fixed point nor transverse/conjugate axes.
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2007-10-22 04:13:50 · answer #1 · answered by Alam Ko Iyan 7 · 3⤊ 0⤋
You do not have enough information to find the hyperbola. For example, there is no way to find the center of the hyperbola or whether it opens vertically or sideways.
2007-10-22 21:17:36 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋
maybe it's a parabola..
2007-10-22 03:24:27 · answer #3 · answered by retsie 2 · 0⤊ 2⤋
can you help me 2 please
2016-05-24 03:51:04 · answer #4 · answered by ? 3 · 0⤊ 0⤋