A ladder 5.7m long rests against a vertical wall at angle f 34*(degrees)02' with the vertical wall. How far is the foot of the ladder from the wall? If the distance of the foot of the ladder from the wall is reduced to half its original distance, at what angle should the ladder be inclined to the wall?
2007-10-22 00:49:38 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
a) B=L sin(f)
B=5.7 sin(34)=3.2
b) now B'=(1/2)B
f=arcSin(B'/L)
f=arSin( (3.2 /2) / 5.7)= 16 degrees
2007-10-22 01:05:52 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
(a) use the sine function:
distance bet. foot and wall = (SINE (angle bet. wall and ladder)) * (length of ladder)
(b) use the sine function still:
desired angle = arcsine ((distance bet. foot and wall / 2) / (length of ladder))
2007-10-22 08:09:59 · answer #2 · answered by bmeneaglor 1 · 0⤊ 0⤋
FIRST USE SIN 34*=PERPENDICULAR/HYPOTENOUS
NOW WE GOT THE PERPENDICULAR & HYPOTENOUS
NOW WE CAN FIND THE BASE BY:-
TAN 34*=HYPOTENOUS/BASE NOW WE FOUND ALL THE LENGTH
NOW REDUCE THE BASE TO HALF &YOU CAN FIND THE HEIGHT OF THE NEW IMAGE THAT IS ASKED HERE.
2007-10-22 08:04:15 · answer #3 · answered by mahipal sah 1 · 0⤊ 0⤋