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How much heat is necessary to change 295 g of ice at -10°C to water at 20°C?
kcal

2007-10-21 23:17:19 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

The heat capacity of water: 4.1813 J/g•K
The heat capacity of ice: 2.114 J/g•K
The heat of fusion: 333.55 J/g
The necessary heat is:
{(0 + 10)*2.114 + 333.55 + (20 - 0)*4.1813}*295 = 129.3 (kJ) = 30.9 kCal.

2007-10-24 15:44:30 · answer #1 · answered by Hahaha 7 · 0 0

.460 circumstances specific warmth potential in joules of water that's approximately 4200j yet you would be able to desire to look that up interior the question. circumstances that via 30 to get to respond to eg mass circumstances SHC circumstances temp substitute. besides the incontrovertible fact that that's a gentle trick question. by way of fact the water variations state you would be able to desire to function in Mass circumstances specific warmth of liquifaction lower back look it up. each so often it has a distinctive call besides the incontrovertible fact that it capacity the substitute of state capacity. The question would desire to offer you the two values you like? The solutions above mine forgot the substitute of state area. additionally prevalent as latent warmth.

2016-11-09 04:27:55 · answer #2 · answered by Anonymous · 0 0

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