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3 answers

5x/x^2 = 5/x , therefore no need for substitution.

integral of (3x^3 + 5/x) dx = (3/4)x^4 + 5lnx

2007-10-21 18:20:32 · answer #1 · answered by Anonymous · 0 0

No need to.

Separate so you have:
Int (3x^3) dx + Int(5x/x^2)dx
= (3/4)x^4 + Int(5/x)dx
= (3/4) x^4 + 5lnx +C

2007-10-21 18:18:19 · answer #2 · answered by Verona A. 1 · 0 0

3x^3 + 5x/x^2
=3x^3 + 5/x

answer: 3x^4/4+5lnx+C

2007-10-21 18:21:33 · answer #3 · answered by iyiogrenci 6 · 0 0

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