I need help with these two question I have tried to figure them out but i need the process to find the answer.

Question

the area of the figue 40ft, 15ft, 15ft, 50ft.

Then the other one is on the volume of the solid 12in, 6in, 6in.

Please help I am very confused, I am looking at my class book and just don't get it for some reason.

Thank you!! :)

Answer 1

You really haven't said enough about the the shapes/solids.
The quadrilateral could be any shape, even if you have the lengths in order.
The solid is some sort of prism, I think. But more info is needed to answer this question.

Answer 2

The first figure is a trapezoid and the area of the same is 63.6396 (correct upto 4 places after decimal) sq ft. The height of the trapezoid is 10x (square root of 2)ft while the sides are 40ft and 50ft. Formula is A=(h/2)x(b1+b2)

The second figure is a cuboid with length=12", height = 6" and breadth = 6 ". So the volume is simple lxbxh, i.e., 432 cubic inches. You may also convert the same in cubic feet by dividing each l, b and h by 12. So, in cubic feet, the answer would be (432)/(12x12x12), i.e., 0.25 cubic ft or 1/4 cubic feet.