help find x
2007-10-21 18:06:50 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
7 x ² - 28 x - 35 = 0
x ² - 4 x - 5 = 0
(x - 5) (x + 1) = 0
x = 5 , x = - 1
2007-10-22 04:55:09 · answer #1 · answered by Como 7 · 0⤊ 0⤋
6x^2 - 22x - 8 = -x^2 + 6x +27
6x^2 + x^2 - 22x - 6x - 8 - 27 = 0
7x^2 - 28x - 35 = 0
x^2 - 4x - 5 = 0
x^2 - 5x + x - 5 = 0
x(x-5) +1(x-5) = 0
(x+1)(x-5) = 0
x = -1 or x = 5
2007-10-22 01:14:03 · answer #2 · answered by doctor_T 2 · 1⤊ 0⤋
6x^2 - 22x - 8 = -x^2 + 6x +27
6x^2 + x^2 - 22x - 6x - 8 - 27 = 0
7x^2 - 28x - 35 = 0
x^2 - 4x - 5 = 0
x^2 - 5x + x - 5 = 0
x(x-5) +1(x-5) = 0
(x+1)(x-5) = 0
x = -1 or x = 5
2007-10-22 01:13:13 · answer #3 · answered by Shreya S 3 · 1⤊ 0⤋
6x² - 22x - 8 = -x² + 6x + 27
Move all terms to one side:
7x² - 28x - 35 = 0
7(x² - 4x - 5) = 0
x² - 4x - 5 = 0
x² - 5x + x - 5 = 0
x(x-5)+1(x-5) = 0
(x+1)(x-5) = 0
x = {-1, 5}
2007-10-22 01:12:01 · answer #4 · answered by gudspeling 7 · 1⤊ 0⤋
6x^2 - 22x - 8+x^2 - 6x -27=0
7x^2-28x-35=0
a=7
b=-28
c=-35
2007-10-22 01:12:40 · answer #5 · answered by iyiogrenci 6 · 0⤊ 3⤋
7x^2-28x-35=0
7(x^2-4x-5)=0
7(x-5)(x+1)=0
x=5,-1
2007-10-22 02:11:43 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋