x^2 - 8x - 27 = -5x - 9?

Question

plxx help

Answer 1

x² - 3x - 18 = 0
(x - 6)(x + 3) = 0
x = 6 , x = - 3

Answer 2

x^2 - 8x - 27 = -5x - 9 ADD 5x + 9 to both sides
x^2 - 8x - 27 + 5x + 9 = 0
x^2 -3x - 18 = 0 FACTOR
(x - 6)(x + 3) = 0 Set either term = 0

IF x - 6 = 0 THEN x = 6
IF x +3 = 0 THEN x = -3
ANSWER x = 6 and x= -3

CHECK
x^2 - 8x - 27 = -5x - 9
for x = 6
(6)^2 - 8(6) - 27 = -5(6) - 9
36 - 48 -27 = -30 - 9
-39 = -39 checks out

x^2 - 8x - 27 = -5x - 9
for x = -3
(-3)^2 - 8(-3) - 27 = (-5)(-3) - 9
9 + 24 - 27 = 15 - 9
6 = y checks out

Answer 3

x^2 - 8x - 27 = - 5x - 9
x^2 - 3x - 18 = 0
(x - 6)(x + 3) =0

Answer: x is either 6 or - 3

Proof (where x is 6):
6^2 - 8(6) - 27 = - 5(6) - 9
36 - 48 - 27 = - 30 - 9
- 39 = - 39

Proof (where x is - 3):
- 3^2 - 8(- 3) - 27 = - 5(- 3) - 9
9 + 24 - 27 = 15 - 9
6 = 6

Answer 4

equate to zero:

x^2-8x+5x-27+9=0, simplify:

x^2 -3x -18 = 0, get the factors:

(x - 6)(x + 3) = 0, to get the values of x

x = 6; x = -3

Answer 5

x^2 - 8x - 27 = -5x - 9

x^2 - 3x - 27 = - 9 {add 5x to both sides}

x^2 - 3x - 18 = 0 {add 9 to both sides}

(x - 6)(x + 3) = 0 {factor the trinomial}

x = 6, x = -3 {set each factor to zero}

Answer 6

x={3,6}
you subtract -5x and -9 so that
0 is on one side. and then you
factor x^2-3x-18=0. get it?

kIMMY n.

Answer 7

x^2-3x-18=0
(x-6)(x+3)=0
x=6;-3