2x^2-3x+4 - factor?

Question

factor in steps please:

2x^2-3x+4

Answer 1

2x^2-3x+4
no factors


but there are imaginary factors
delta is less than zero

Answer 2

since you cannot break it down to a (x )(x ) format
you will need to use something called the quadratic formula.

This is the quadratic formula (http://media.nasaexplores.com/lessons/01-003/images/quadform.gif)

as you can see the quadratic equation is seperated by a, b and c.

Well...

your equation is 2x^2 - 3x + 4
you can break that equation into three pieces (a, b, c)
all you do is take out the numbers and forget about the x's and exponents (ex: 2x^2 simply becomes 2)

a = 2
b = 3
c = 4

And then you plug it into your quadratic equation.

In the end you should get:

3±√23 / 4

or

3±√23
---------
4

Answer 3

You can only do it with imaginary numbers
Use the quadratic equation

x = [3 +(-) √(9-4(2)(4)] / 4

x = (3 + 23i)/4 , (3- 23i)/4

Answer 4

= 2x^2 - 3x + 4
It cannot be factored further.