Can anyone show me how to do this physics problem?

Question

There are two blocks connected by a sting and tied to a wall. The mass of the lower block is 1 kg; the mass of the upper block is 2 kg. Given that the angle of the incline is 31 degrees, find the tension in (a) the string connecting the two blocks and (b) the string that is tied to the wall.

Answer 1

Forces acting on lower block: m1*g downward, N1 - normal force perpendicular to the incline, T1 tension in string between 2 blocks upward along the incline. In equlibrium the sum of forces' components along the incline should be 0:
T1 - m1*g*sinA = 0, so T1 = m1*g*sinA
Forces acting on upper block: m2*g downward, N2 - normal force perpendicular to the incline, T1 tension in string between 2 blocks downward along the incline, T2 tension in string connected to wall directed up along the incline. In equlibrium the sum of forces' components along the incline should be 0:
T2 - T1 - m2*g*sinA = 0
T2 = T1 + m2*g*sinA = m1*g*sinA + m2*g*sinA = (m1 + m2)*g*sinA

Answer 2

Vectors.

First, find the force that the 1kg block pulls on the upper block.

F=Sin (31)m *g, where m is the 1 kg

Second for the 1 and 2 kg blocks pulling against the wall

F = Sin (31) m *g where m = 3 kg.