Please explain how to solve this problem.
2007-10-21 14:44:19 · 9 answers · asked by Griselle A 1 in Science & Mathematics ➔ Mathematics
a - 5 = - 2
a = 3
2007-10-24 06:42:58 · answer #1 · answered by Como 7 · 0⤊ 0⤋
k well 3(a-5)=-6
first: distribute 3(a-5) so 3 times a= 3a and 3times 5= 15
=3a-15=-16
= then you do the opposite from both sides so...
add -15 to -16 which is like adding 2 negatives. so it would be -21
=3a=-21
=now do opposite of 3a to both sides so...3 divided by 3 cancells eachother out and 3 divided by -21
a= -7
there u go!!! hope i helped
(just 2 let u know carrra was wrong)
2007-10-21 14:55:54 · answer #2 · answered by sarah 2 · 0⤊ 0⤋
1. First, distribute the 3.
3a-15= -6
2. Group like terms.
3a= -6+15
3. Simplify.
3a= 9
a=3
2007-10-21 14:47:53 · answer #3 · answered by carrra 2 · 0⤊ 0⤋
thats a weird problem because if u use the distruibutive property u get 3*a-3*15 whitch is 3a-15 whitch means that 3a has to equal somthing less then 5, so if a=3 then 3a would equal 9 so 9-15=(-)6, hope that helped a little
2007-10-21 14:48:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
distribute the 3 over to the a and the -5.....3a-15= -6.....then add 15 to both sides.....3a= -9.....divide 3 off both sides.....a= -3
2007-10-21 14:49:08 · answer #5 · answered by Anonymous · 0⤊ 0⤋
distribute the 3 and you get 3a-15=-6
add 15 to both sides and you get 3a=9
divide both sides by 3 you get a=3
2007-10-21 14:48:17 · answer #6 · answered by ridr90 2 · 0⤊ 0⤋
3(a-5)= -6
3a-15= -6
3a= -6+15
3a=9
a=3
2007-10-21 14:55:48 · answer #7 · answered by Vida Joy 3 · 0⤊ 0⤋
distribute first, 3a-3(5)=-6
3a-15=-6
3a=-6+15
3a=9
a=9/3
a=3
2007-10-21 15:32:18 · answer #8 · answered by Jenny H 1 · 0⤊ 0⤋
first u have to distribute-3a-15=-6
then you have to add 15 to get rid of it so you'll just have 3a on one side so..3a=9
then you divide...so a=3 and there you go...
2007-10-21 14:47:59 · answer #9 · answered by Anonymous · 0⤊ 0⤋