PHYSICS question!!!?

Question

Given the situation in the figure below. The mass m1 is 0.64 kg and it is located at x1 = 30 cm. The pivot point is represented by the solid triangle located at x = 45 cm. The mass of the meter stick (mms = 0.40 kg) is located at its geometric center, xms = 50 cm. The mass m2 is 0.25 kg and it is located at x2 = 80 cm. Calculate the net torque (in N⋅m with the proper sign) due to these three weights. Use g = 9.8 m/s2.

There is a picture of a ruler with weights hanging at the locations listed above.

Answer 1

Torque is force x distance. You might use a spreadsheet to do the multiplications and add them all up.

Force is mass x gravity.