What is the implicit differentiantion of tan(x+y)...find dy/dx?

Answer 1

y´= [1+tan^2(x+y)]*(1+y´) supposing that you have y=tan(x+y)
y'= 1+y´+tan^2(x+y) +y´*tan^2(x+y) so y´= -[1+tan^2(x+y)]/tan^2(x+y)