Find the area of a circle with a circumference of 28 pi (meters)?

Answer 1

C = 28 π = 2π r
r = 14 m
A = π (14)² m ²
A = (22/7) (14) (14) m ²
A = 44 x 14 m ²
A = 616 m ²

Answer 2

First, we know that the area of a circle is equal to pi times its radius squared (or A=pi*r^2).

We also know that the circumference of a circle is equal to pi times its diameter (or c=pi*d), which is also equal to pi times two times the radius (or c=2*pi*r) since the diameter is twice the radius.

We are told that the circumference of a circle = 28*pi

so:
c=28*pi
2*pi*r=28*pi

simplify to:
r=14 [cancel the pi's & divide 28 into 2]

so now we can input r=14 into our first equation:
A=pi*r^2
A=pi*(14)^2

thus:
A=196*pi m^2

Answer 3

28*pi = 2*pi*r

Solving for r gives r = 14 (the pi's cancel out)

Now A=pi*r^2

So A = 196*pi m^2 (neters squared)

Answer 4

area = pi(r^2)
and cirm = 2(pi)(r)
so 28(pi) = 2(pi)(r)
or r = 14

so area = pi(14^2) mtrs squared

so area = 196(pi) mts srqrd
if we let pi = 22/7
then area = 196(22)/7 = 28(22) = 616 mtrs sqrd.