A 2kg object is moving across a table at a speed of 2.0 m/s againt a force of friction of 6.0 n. The applied force is suddenly increased by 1.0n. How fast will oject be moving after 3.0s
2007-10-21 06:27:09 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
2.0 is at constant speed
2007-10-21 06:36:56 · update #1
please show how its done thx
2007-10-21 06:39:38 · update #2
Is 2.0 m/s constant speed?
If it was then the sum of forces is 0.
If 1 N is added then the object will accelerate at
a=dF/m
dF - increase in force and
m - mass of the object
V=at+V0
then
V=(dF/m )t + V0
V=(1/2)3 + 2.0=3.5 m/s
What if V0 was not constant?
then
V=(a + a')t + V0
a'=Ff-f
F- force forward
f - force of friction = 6N
2007-10-21 06:33:25 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
m=2kg
u=2m/s
t=3
initialy moving at 2m/s means no acceleration means applied force = friction. therefore aplied force = 6.0n
increase it by 1.0n and the aplied force bcomes 7.0n
f=ma
force = aplied force minus the friction
7-6=2a
1=2a
a=0.5m/s^-2
v=u +at
v=2 + (0.5)(3)
v= 2 + 1.5
v = 3.5 m/s after 3 seconds
2007-10-21 13:39:22 · answer #2 · answered by suey 2 · 0⤊ 0⤋