(x-10)(x-2)=-2
I'm not sure if I am doing this right. anyone who can show me how to do this please. Thankyou
2007-10-21 03:19:54 · 7 answers · asked by sumguy 1 in Science & Mathematics ➔ Mathematics
Expand the left side and then add 2 to both sides (to get rid of that -2 on the right):
x^2 - 12x + 22 = 0
This hasn't rational factors, so if you use the quadratic formula (I'm assuming you know it)
x = [-b +/- sqrt(b^2 - 4ac)]/2a
.. = [12 +/- sqrt(144 - 88)]/2
.. = 6 + sqrt(14) or 6 - sqrt(14)
Of the earlier answers, notice sathyanarayanan k did OK except for using -12, whereas -b = 12 since b = -12.
2007-10-21 03:33:14 · answer #1 · answered by Hy 7 · 0⤊ 0⤋
x^2-12x+20=-2
x^2-12x+22=0 use quadradic formla (but for exercise complete the square x^2+bx+c=0
x^2-12x =-22 1/2 b square and add to both sides
x^2-12x +36=-22+36
(x-6)^2=14
x-6=+-Sqr14
x=6+-sqr14 complete the square on ax^2+bx+c=0
divide by a first x^2+(b/a)x +c/a=0
move c/a to right side; takehalf coef x (here is (b/2a)) which you square and add to both sides . Continue and you have derived the quadratic formula!
2007-10-21 04:25:35 · answer #2 · answered by rwbblb46 4 · 0⤊ 0⤋
I would solve this just as quadratic equation x^2-12x+22=0.
2007-10-21 03:31:34 · answer #3 · answered by Wintermute 4 · 0⤊ 0⤋
x2-12x+22=0 (using distributive law)
so x= ((12+-sqrt(144 -88)/2 = 6+-sqrt(14)
2007-10-21 03:34:28 · answer #4 · answered by santmann2002 7 · 0⤊ 0⤋
Expand Brackets
Collect terms
Solve quadratic
x² - 10x - 2x + 20 = -2
x² -12x + 22 = 0
Should get you started ... :-)
2007-10-21 03:32:39 · answer #5 · answered by Rod Mac 5 · 1⤊ 0⤋
x^2-2x-10x+20+2=0
x^2-12x+22=0
x=(-12+(12^2-4(1)(22))^.5)/2(1) or (-12-(12^2-4(1)(22))^.5)/2(1)
x=-2.5834 or -9.74
2007-10-21 03:31:13 · answer #6 · answered by sathyanarayanan k 2 · 0⤊ 0⤋
you said method of choice ?
what are your choices ?
2007-10-21 03:36:44 · answer #7 · answered by calculus 1 · 0⤊ 0⤋