how do u expand the equation: (x+1)(x-1)(x-3)?
2007-10-21 00:08:20 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Do it in pieces based on the associative property of multiplication: A*B*C=(A*B)*C
In your case,
A*B = (x+1)*(x-1) = (x²-1)
Then
(A*B)*C = (x²-1)*(x-3).
Appying FOIL we get
x³-3x²-x+3
2007-10-21 00:15:34 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Expand two of them first so:
(x+1)(x-1)(x-3)
= (x^2 -x + x -1)(x-3)
= (x^2 - 1)(x-3)
= (x^3 -x - 3x^2 +3)
= x^3 - 3x^2 - x + 3
2007-10-21 00:16:07 · answer #2 · answered by blastedsand 2 · 0⤊ 0⤋
Multiply it out. That's part of the reason that you learned how to multiply polynomials in basic algebra.
And, by the way, that is -not- an equation. It is an expression. Equations contain an = in them âº
Doug
2007-10-21 00:18:02 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋