I have worked out how to do
cos = root 3 on 2
As
30 degrees, and 330 degrees
Im just having some trouble with the others
2007-10-20 22:47:15 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
225 and 315 because quad 3 and 4 would be negative for sine and sine of those angles are negative radical 2 over 2
2007-10-20 22:52:34 · answer #1 · answered by cow9634 3 · 0⤊ 0⤋
cosec x = - sqrt(2)
implies
sin x = -1/sqrt(2)
We know sin is negative in 3rd and 4th quadrants.
and as we know that sin is 1/ sqrt(2) for 45 degrees in the 1st quadrant, Thus in the 3rd and 4th quadrant it would be 180 + 45, and 360 - 45 respectively
So the solutions are
225 degrees and 315 degrees
2007-10-21 00:11:19 · answer #2 · answered by gauravragtah 4 · 0⤊ 1⤋
1 / sin x = - â2
sin x = - 1 / â2
x = 225° , x = 315° (3rd and 4th quadrants)
2007-10-21 08:31:43 · answer #3 · answered by Como 7 · 1⤊ 0⤋