a 450 kg mass is accelerated at 2.5 m/s2. how much distance will have been covered after 3.5s?

Answer 1

accelaration is 2.5x
the intergral (or displacement is) is = (x^2) /2 *2.5
so you just put 3.5 into that function and you have your answer.
hope that helps

Answer 2

there is no need to take the mass into account.
Using the second eq. of motion--

x=ut + (1/2)a(t^2), where u is the starting speed (m/s), t is time (s), a is acceleration (m/s^2), and x is distance (m)
we have to assume that body starts from rest
x=0*3.5 + 0.5*2.5*(3.5^2)= 0 +15.3125
=15.31

Answer 3

An expected equation to use would be
x=ut + 0.5a(t^2), where u is the starting speed (m/s), t is time (s), a is acceleration (m/s^2), and x is distance (m)

x=0*3.5 + 0.5*2.5*(3.5^2)= 0 +15.3125
=15m (to 2 significant figures)

Answer 4

S = ut + ½at²
s = 0 x 3.5 + ½ x 2.5 x (3.5)²
S = 0 + 1.25 x 12.25 = 15.3125 metres
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Answer 5

The formula for distance traveled under constant acceleration a is

s = 0.5*a*t^2

s = 0.5*2.5*(3.5)^2

s = 15.31 m