English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

A boat of mass 250 kg is coasting, with its engine in neutral, through the water at speed 3.00 m/s when it starts to rain. The rain is falling vertically, and it accumulates in the boat at the rate of 10.0 kg/hr.

The drag is proportional to the square of the speed of the boat, in the form F_d= 0.5 v^2. What is the acceleration of the boat just after the rain starts? Take the positive x axis along the direction of motion.
Express your answer in meters per second per second.

2007-10-20 20:28:13 · 1 answers · asked by Komodork 3 in Science & Mathematics Physics

1 answers

Acceleration a = F/m Since F is a drag force, the acceleration is negative

a = -0.5*v^2 / (250 + 10*t) just as the rain starts, t = 0; the acceleration at t = 0 is

a = -0.5*3.00^2/250 = -0.018 m/sec^2

2007-10-20 20:52:12 · answer #1 · answered by gp4rts 7 · 0 7

fedest.com, questions and answers