sq. rt. (8+6i)(6i-8)
2007-10-20 16:01:13 · 6 answers · asked by amy f 1 in Science & Mathematics ➔ Mathematics
I believe it is 10 sq.rt. -1, when you foil you should get: 48i -64 + 36isqrd -48i, the 48i and -48i cancell, the i sqrd is -1 so, -64-36 under the radical, is -100 or 100 (-1) which comes out to 10 radical -1. ;) HTH
2007-10-20 16:12:04 · answer #1 · answered by ASPIRE 2 · 0⤊ 0⤋
FOIL
sqrt(48i+36i^2-64-48i)
=sqrt(-36-64)
=sqrt(-100)
=10i
2007-10-20 16:15:16 · answer #2 · answered by Amelia 6 · 0⤊ 0⤋
Rewrite it as: (6i+8)(6i-8)
Then it becomes: 36i^2 - 64
Which after taking the sq.rt. is: 6i - 8
2007-10-20 16:09:38 · answer #3 · answered by Robert S 7 · 0⤊ 0⤋
wow I already took algebra last year and don't even know what that is
2007-10-20 16:10:36 · answer #4 · answered by slob_15 3 · 0⤊ 0⤋
this is not the place to ask that kind of questions .... ck with your parents or school mates.
2007-10-20 16:04:56 · answer #5 · answered by surreal_survivor 3 · 0⤊ 0⤋
10i
2007-10-20 16:05:01 · answer #6 · answered by Frostie K 1 · 0⤊ 0⤋