given the function g(x)=x*2-2x+1,find the value of g(1).?

Answer 1

Step 1: write out the equation g(1)=x^2-2x+1
Step 2: subsitute 1 for x= g(1)=1^2-2(1)+1
Solve:
(1^2) -2(1)+1
1-2+1
-1+1=0

Answer 2

g(1)= 1*2-2(1)+1
= 2-2+1
= 1

Answer 3

g(1) = 1*2 - 2*1 + 1 = 2 - 2 + 1 = 1

Answer 4

g(x)=x^2-2x+1
g(1), this means everywhere you see an x in that equation, replace it with 1 and evaluate the equation. Therefore:

g(1)=(1)^2-2(1)+1
g(1)=1-2+1
g(1)=0

And if you want to write x squared you write it as x^2, not x*2

Answer 5

to answer this one, we should substitute 1 for x because g(x)=g(1) and then divide both sides by g you will get x=1 so you will substitute 1 for x

this is what will happen

1*2-2(1)+1
2-2+1
1

so
g(1)=1

hope this helps.......

Answer 6

Simply substitute the x into equation.

g(1)=1*2-2(1)+1.......Multiply first
g(1)=2-2+1.....Subtract then add
g(1)=1

The answer is g(1)=1

Answer 7

g(x) = x² - 2x + 1
g(1) = 1 - 2 + 1
g(1) = 0