Can someone please help me with this problem. Thank you.
2007-10-20 15:12:05 · 8 answers · asked by Kevin G 2 in Science & Mathematics ➔ Mathematics
(2x+5)(2x-5)
2007-10-20 15:18:33 · answer #1 · answered by Anonymous · 0⤊ 0⤋
If 4x62-25=0
4x^2=25 step-1
so:
x^2=25/4 step-2
so:
x=5/2 step-3
and
x=-5/2
If only written 4x^2-25
(2x)^2-(5)^2
2007-10-20 22:25:02 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(2x - 5)*(2x + 5)
x = 5/2 , x = -5/2
2007-10-20 22:15:31 · answer #3 · answered by BoboTheClown 3 · 0⤊ 1⤋
4x^2-25
=2^2*(x^2)-(5^2)
=(2x)^2 - 5^2
now gimme my stars:)
2007-10-20 22:15:57 · answer #4 · answered by sid 4 · 0⤊ 2⤋
(2x - 5)(2x + 5)
2007-10-21 03:12:42 · answer #5 · answered by Como 7 · 0⤊ 0⤋
(2x-5)(2x+5)
2007-10-20 22:41:53 · answer #6 · answered by Anonymous · 0⤊ 0⤋
(2x+5)(2x-5)
2007-10-20 22:21:46 · answer #7 · answered by drake_zula 2 · 1⤊ 0⤋
(2x+5)(2x-5)
2007-10-20 22:14:37 · answer #8 · answered by kelsey 7 · 2⤊ 0⤋