A = 1/2h(B+b)..... get b by itself?

Answer 1

1/2*h(B+b)=A
h(B+b)=2A[multiplying both sides by 2]
B+b=2A/h[dividing both sides by h]
b=(2A/h) -B[subtracting B from both sides]

Answer 2

If b and B are the same thing, then:

A/(1/2h)/2 = B or A divided by 1/2h divided by 2 is B

I'm too lazy to do it with b and B being different...

Answer 3

A = 1/2h(B+b)
Distribute ~ A = 1/2hB+1/2hb
Divide by 1/2h ~ A/(1/2h) = B+b
Subtract B ~ A/(1/2h)-B = b

Answer 4

A=1/2h(B+b)
A(2)=2(1/2)h(B+b)
A(2)/h=h(B+b)/h
A(2)-B/h=B-B+b/h
(A(2)-B)/h=b

Answer 5

Just use simple algebra, however it's not clear what your original formula is.

Is it... A = 1/2h x (B+b) or A = 1/2 h / (B+b)

Answer 6

divide both sides by 1/2h
get : A
--- = (B+b)
1/2h
subtract B

A
--- - B = (b)
1/2h

Answer 7

While there are short cuts, it is best to first eliminate fractions from an equation before trying to solve. Be sure to note that the formula should be written as

A = (1/2)h(B+b) so multiply through by 2 to get

2A = h(B+b) Now distribute the h to get

2A = Bh +bh. Since you want b, subtract Bh to get

2A -Bh = bh and finally divide both sides by h to get

(2A-Bh)/h = b.

This answer can also be written as

b = (2A-Bh)/h = 2A/h - B

The first form is preferable since it is just one term.

Answer 8

1 A= !/2hB + 1/2hb (distribute)

2 A-1/2hB=1/2hb (subtract from both sides)

3 (A-1/2hB)/(1/2h)=b (divide both sides by 1/2h)

so b=(A-1/2hB)/(1/2h)
you can simplify more, but it's unneccessary.

Answer 9

I assume you mean A = (1/2)*h*(B+b) and not A = 1/(2*h*(B+b))
b = 2*A/h-B

Answer 10

divide a by 1/2h
and subtract B

Answer 11

Solving for b

A = 0.5h(B+b)

multiply by 2 both sides

2A = B + b

solving for b

b = 2A-B

and that's how is done