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(a) 14.7
(b) 44.0
(c) 78.0
(d) 26.0

2007-10-20 13:37:01 · 1 answers · asked by Edgardo M 1 in Science & Mathematics Chemistry

1 answers

Atomic weights: Al=27 O=16 H=1 Al(OH)3=78

78gAl(OH)3/1molAl(OH)3 x 1molAl(OH)3/3eqwtAl(OH)3 = 26.0g Al(OH)3 per eq wt.

2007-10-20 13:50:58 · answer #1 · answered by steve_geo1 7 · 0 0

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