5 - i / -7 + 2i
I think the i's mean imaginary numbers or something.
Please tell how you got the answer too because I need to understand it for a test coming up. Thanks so much.
2007-10-20 13:26:52 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(5 - i) / (-7 + 2i)
(5 - i)(-7 - 2i) / ((-7 + 2i)(-7 - 2i))
(-35 + 7i - 10i - 2) / (49 + 4)
(-37 - 3i) /53
-37/53 - 3/53 i
2007-10-20 13:36:19 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
multiply both top and bottom by the congugate of -7 + 2i, which is -7 - 2i
[(5-i) (-7-2i)] / [(-7+2i) (-7-2i)]
foil
(-35 - 10i + 7i - 2i^2) / (49 - 4i^2)
simplify
(-35 - 3i - 2i^2) / (49 - 4i^2)
i^2 = -1
(-35 - 3i -+2(-1) ) / (49 - 4(-1))
simplify
(-37 - 3i) / (53)
-37/53 - 3i/53
2007-10-20 13:40:31 · answer #2 · answered by 7 · 0⤊ 0⤋
i have no idea it looks messed up
2007-10-20 13:34:41 · answer #3 · answered by puerto rifa 1 · 0⤊ 0⤋